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A soft drink machine outputs a mean of 22 ounces per cup. The machine's output is normally distributed with a standard deviation of 3 ounces. What is the probability of filling a cup between 23 and 24 ounces? Round your answer to four decimal places.

µ = 22; σ = 3 ounces
    p(23 < x>      z=  (23-22)/3=0.33 
    z=  (24-22)/3=0.67
    P(Z < 0>            P(Z < 0>

    Probability of filling between 23 and 24 ounces = 0.7486 – 0.6293 = 0.1193

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